【海贼王编程冒险 – C语言海上篇】怎样用C语言实现简单的扫雷游戏？

目录

1 -> test.c

2 -> game.c

3 -> game.h

1 -> test.c

#define _CRT_SECURE_NO_WARNINGS 1#include "game.h"void menu(){printf("************************************\n");printf("********* 1.play********\n");printf("********* 0.exit********\n");printf("************************************\n");}void game(){//show数组为排查出的雷的信息char show[ROWS][COLS] = { 0 };//mine数组为布置好的雷的信息char mine[ROWS][COLS] = { 0 };//初始化棋盘InitBoard(show, ROWS, COLS, '*');InitBoard(mine, ROWS, COLS, '0');//打印棋盘DisplayBoard(show, ROW, COL);//布置雷SetMine(mine, ROW, COL);//DisplayBoard(mine, ROW, COL);//排查雷FineMine(mine, show, ROW, COL);}int main(){int input = 0;srand((unsigned int)time(NULL));do{menu();printf("请选择:>");scanf("%d", &input);switch (input){case 1:game();break;case 0:printf("退出游戏\n");break;default:printf("输入错误，请重新输入。\n");break;}} while (input);return 0;}

2 -> game.c

#define _CRT_SECURE_NO_WARNINGS 1#include "game.h"//初始化棋盘void InitBoard(char board[ROWS][ROWS], int rows, int cols, char set){memset(&board[0][0], set, rows * cols * sizeof(board[0][0]));}//打印棋盘void DisplayBoard(char board[ROWS][ROWS], int row, int col){printf("******扫雷******\n");for (int j = 0; j <= col; j++){printf("%d ", j);}printf("\n");for (int i = 1; i <= row; i++){printf("%d ", i);for (int j = 1; j <= col; j++){printf("%c ", board[i][j]);}printf("\n");}}//布置雷void SetMine(char mine[ROWS][COLS], int row, int col){int cnt = EASY_COUNT;while (cnt){int x = rand() % row + 1;int y = rand() % col + 1;if (mine[x][y] == '0'){mine[x][y] = '1';cnt--;}}}//计算周围雷的数量int GetMineCount(char mine[ROWS][COLS], int x, int y){return (mine[x - 1][y - 1] +mine[x - 1][y] +mine[x - 1][y + 1] +mine[x][y - 1] +mine[x][y + 1] +mine[x + 1][y - 1] +mine[x + 1][y] +mine[x + 1][y + 1] - 8 * '0');}//排查雷void FineMine(char mine[ROWS][COLS], char show[ROWS][COLS], int row, int col){int x = 0;int y = 0;int win = 0;while (win ");scanf("%d %d", &x, &y);if (x >= 1 && x = 1 && y <= col){if (mine[x][y] == '1'){printf("很遗憾，排雷失败。\n");DisplayBoard(mine, ROW, COL);break;}else{int cnt = GetMineCount(mine, x, y);show[x][y] = cnt + '0';DisplayBoard(show, ROW, COL);win++;}}else{printf("坐标输入错误，请重新输入\n");}}if (win == row * col - EASY_COUNT){printf("恭喜你排雷成功!!!\n");}}

3 -> game.h

#pragma once#include #include #include //棋盘大小#define ROW 9#define COL 9#define ROWS ROW + 2#define COLS COL + 2//雷的个数#define EASY_COUNT 10//初始化棋盘void InitBoard(char board[ROWS][ROWS], int rows, int cols, char set);//打印棋盘void DisplayBoard(char board[ROWS][ROWS], int row, int col);//布置雷void SetMine(char mine[ROWS][COLS], int row, int col);//计算周围雷的数量int GetMineCount(char mine[ROWS][COLS], int x, int y);//排查雷void FineMine(char mine[ROWS][COLS], char show[ROWS][COLS], int row, int col);

代码里的注释感觉已经很清楚啦，就不多讲解啦

感谢各位大佬的支持！！！