【C语言项目合集】这十个入门必备练手项目，让C语言对你来说不再难学！

适合刚入门C语言的编程学习小白的十个练手项目，每个都很经典且实用，让你学完C语言不再迷茫！

一、多关卡推箱子

主要考察知识点：数组

开发工具：Visual Studio2019、EasyX图形库

效果图：

完整代码：

/*--------------------------------------■ 墙壁 1☆目的地3★箱子4○ 箱子到达目的地 3+4=7♀ 人5人到达目的地 8空格 路01.设计关卡（定义关卡，判断关卡2.找素材，用贴图的办法做一个可视化的推箱子游戏*/#include #include #include #include #include #pragma comment(lib,"winmm.lib")//静态库资源//用三维数组特定的数字描绘出这个地图int cas = 0;int map[4][8][8] ={1,1,1,1,1,1,1,1,1,3,4,0,0,4,3,1,1,0,1,3,0,1,0,1,1,0,1,4,0,1,0,1,1,0,0,5,0,0,0,1,1,0,1,0,0,1,0,1,1,3,4,0,0,4,3,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,3,4,0,0,4,3,1,1,0,1,3,0,1,0,1,1,0,1,4,0,1,0,1,1,3,4,5,0,0,0,1,1,0,1,0,0,1,0,1,1,3,4,0,0,4,3,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,3,4,0,0,4,3,1,1,0,1,3,0,1,0,1,1,0,1,4,0,1,0,1,1,3,4,0,0,4,3,1,1,0,1,0,0,1,0,1,1,3,4,5,0,4,3,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,3,4,0,0,4,3,1,1,0,1,3,0,1,3,1,1,3,1,4,0,1,4,1,1,4,0,0,0,5,0,1,1,0,0,0,0,1,0,1,1,3,4,0,0,4,3,1,1,1,1,1,1,1,1,1,};IMAGE img[6];//6张图片，6个名字void loadResource(){loadimage(img + 0, "0.bmp", 50, 50);loadimage(img + 1, "1.bmp", 50, 50);loadimage(img + 2, "3.bmp", 50, 50);loadimage(img + 3, "4.bmp", 50, 50);loadimage(img + 4, "5.bmp", 50, 50);loadimage(img + 5, "7.bmp", 50, 50);}//绘制地图voiddrawGraph(){for (int i = 0; i < 8; i++){for (int j = 0; j < 8; j++){//算贴图的坐标int x = 50 * j;int y = 50 * i;switch (map[cas][i][j]){case 0://一个汉字符号占用两个位置//printf("");putimage(x, y, img + 0);break;case 1:putimage(x, y, img + 1);//printf("■");break;case 3:putimage(x, y, img + 2);//printf("☆");break;case 4:putimage(x, y, img + 3);//printf("★");break;case 5:case 8:putimage(x, y, img + 4);//printf("人");break;case 7:putimage(x, y, img + 5);//printf("●");break;}}//printf("\n");}}//玩游戏void keyDown(){int userKey = _getch();//不可见输入//定位：找到人的位置int i = 0;int j = 0;for (i = 1; i < 8; i++){for (j = 1; j < 8; j++){if (map[cas][i][j] == 5 || map[cas][i][j] == 8){goto NEXT;}}}NEXT://我们这个游戏用什么按键去玩switch (userKey){case 'W':case 'w':case 72:if (map[cas][i - 1][j] == 0 || map[cas][i - 1][j] == 3){map[cas][i][j] -= 5;map[cas][i - 1][j] += 5;}if (map[cas][i - 1][j] == 4 || map[cas][i - 1][j] == 7){if (map[cas][i - 2][j] == 0 || map[cas][i - 2][j] == 3){map[cas][i][j] -= 5;map[cas][i - 1][j] += 1;map[cas][i - 2][j] += 4;}}break;case 's':case 'S':case 80:if (map[cas][i + 1][j] == 0 || map[cas][i + 1][j] == 3){map[cas][i][j] -= 5;map[cas][i + 1][j] += 5;}if (map[cas][i + 1][j] == 4 || map[cas][i + 1][j] == 7){if (map[cas][i + 2][j] == 0 || map[cas][i + 2][j] == 3){map[cas][i][j] -= 5;map[cas][i + 1][j] += 1;map[cas][i + 2][j] += 4;}}break;case 'a':case 'A':case 75:if (map[cas][i][j - 1] == 0 || map[cas][i][j - 1] == 3){//a+=1a=a+1 复合赋值运算符map[cas][i][j] -= 5;map[cas][i][j - 1] += 5;}if (map[cas][i][j - 1] == 4 || map[cas][i][j - 1] == 7){if (map[cas][i][j - 2] == 0 || map[cas][i][j - 2] == 3){map[cas][i][j] -= 5;map[cas][i][j - 1] += 1;map[cas][i][j - 2] += 4;}}break;case 'd':case 'D':case 77:if (map[cas][i][j + 1] == 0 || map[cas][i][j + 1] == 3){map[cas][i][j] -= 5;map[cas][i][j + 1] += 5;}if (map[cas][i][j + 1] == 4 || map[cas][i][j + 1] == 7){if (map[cas][i][j + 2] == 0 || map[cas][i][j + 2] == 3){map[cas][i][j] -= 5;map[cas][i][j + 1] += 1;map[cas][i][j + 2] += 4;}}break;}}//胜负的判断:int gameOver(){//地图上没有箱子就可以结束for (int i = 0; i < 8; i++){for (int j = 0; j < 8; j++){if (map[cas][i][j] == 4){return 0;}}}return 1;}int main(){loadResource();//定义加载资源函数mciSendString("open 1.mp3", 0, 0, 0);//加载音乐mciSendString("play 1.mp3 repeat", 0, 0, 0);//循环播放音乐资源initgraph(50 * 8, 50 * 8);while (1){drawGraph();if (gameOver()){cas++;//变换关卡if (cas == 4)break;}keyDown();//循环按下按键//system("cls");}closegraph();//关闭窗口return 0;}

二、扫雷

主要考察知识点：数组

开发工具：Visual Studio2019、EasyX图形库

效果图：

完整代码：

#include#include#include#include#include#pragma comment(lib, "winmm.lib")#define ROW 10//定义行列的常量#define COL10 #define MineNum 10//雷的数量#define ImgSize40//图片的尺寸//定义图片资源IMAGE imgs[12];void loadResource(){for (int i = 0; i = 0 && r = 0 && c < COL) && map[r][c] != -1){++map[r][c];}}}}}}//加密格子for (int i = 0; i < ROW; i++){for (int k = 0; k < COL; k++){map[i][k] += 20;}}}//绘制void draw(int map[][COL]){//贴图，根据map里面的数据，贴对应的图片for (int i = 0; i < ROW; i++){for (int k = 0; k =0 && map[i][k]= 19 && map[i][k] = 39)//-1 + 20 +20{putimage(k * ImgSize, i * ImgSize, &imgs[11]);}}}}//鼠标操作数据void mouseMsg(ExMessage* msg,int map[][COL]){//先根据鼠标点击的坐标求出对应的数组的下标int r = msg->y / ImgSize;int c = msg->x / ImgSize;//左键打开格子if (msg->message == WM_LBUTTONDOWN){//什么时候能够打开，没有打开的时候就打开if (map[r][c]>=19 && map[r][c]message == WM_RBUTTONDOWN){PlaySound("./images/rightClick.wav", NULL, SND_ASYNC | SND_FILENAME);//是否能够标记：如果没有打开就能标记if (map[r][c] >= 19 && map[r][c] =39){map[r][c] -= 20;}}}//点击空白格子，连环爆开周围的所有空白格子还有数字row col 是当前点击的格子void boomBlank(int map[][COL],int row,int col){//判断row col位置是不是空白格子if (map[row][col] == 0){for (int r = row-1; r <= row+1; r++){for (int c = col-1; c =0&&r=0&&c=19 && map[r][c]<=28)//没有打开{//每一次调用都会播放一下if (isfirst){PlaySound("./images/search.wav", NULL, SND_ASYNC | SND_FILENAME);isfirst = false;}map[r][c] -= 20;boomBlank(map, r, c);}}}}return;}//游戏结束条件 输了返回-1没结束返回0 赢了返回 1int judge(int map[][COL],int row ,int col){//点到了雷，结束输了if (map[row][col] == -1 || map[row][col] == 19){return -1;}//点完了格子，结束 赢了 点开了100 - 10 = 90 个格子int cnt = 0;for (int i = 0; i < ROW; i++){for (int k = 0; k = 0 && map[i][k] <= 8){++cnt;}}}if (ROW*COL - MineNum == cnt){return 1;}return 0;}

三、贪吃蛇

主要考察知识点：结构体

开发工具：Visual Studio2019、EasyX图形库

效果图：

完整代码：

#include#include#include#include#include#pragma comment(lib,"winmm.lib")/*课程内容：贪吃蛇解析：1，创建界面，绘图，矩形表示 的圣体~ 2，绘制蛇 3，蛇的移动 4，产生食物 5，吃食物 6，游戏输赢判断 7，分数，穿墙。。。。蛇的属性：长度，坐标，方向，速度,是否死亡，分数*/#define WIDTH 800 //窗口的宽高#define HEIGHT 600#define SNAKE_NUM 500//蛇的最大节数enum DIR//蛇的方向{UP,//上DOWN,LEFT,RIGHT,};struct Snake //蛇的结构{int size; //有多少节POINT coor[SNAKE_NUM];//每一节蛇的坐标数组int dir;//蛇的方向int speed;//速度int score;//分数}snake;struct Food//食物{int x;int y;int r;int flag;//是否被吃掉COLORREF color;}food;//初始化数据void GameInit(){//播放背景音乐mciSendString(L"open ./ress/snake_bgm.mp3 alias BGM", 0, 0, 0);mciSendString(L"play BGM repeat", 0, 0, 0);//设置随机数种子srand(GetTickCount());//初始化蛇snake.dir = DIR::RIGHT;//思考：怎么表示蛇的方向？::域运算符snake.score = 0;snake.size = 3;snake.speed = 10;snake.coor[2].x = 10;snake.coor[2].y = 10;snake.coor[1].x = 20;snake.coor[1].y = 10;snake.coor[0].x = 30;snake.coor[0].y = 10;//初始化食物food.color = RGB(rand() % 256, rand() % 256, rand() % 256);food.flag = 1;food.r = rand() % 10 + 5;food.x = rand() % WIDTH;food.y = rand() % HEIGHT;}void GameDraw(){BeginBatchDraw();//防止闪屏//设置背景颜色setbkcolor(RGB(151, 203, 208));cleardevice();//绘制蛇for (int i = 0; i 0; i--)//从蛇尾遍历到蛇头{snake.coor[i] = snake.coor[i - 1];//结构体可以直接赋值//snake.coor[i].x = snake.coor[i - 1].x;//snake.coor[i].y = snake.coor[i - 1].y;}//移动蛇头switch (snake.dir){case UP:snake.coor[0].y -= snake.speed;if (snake.coor[0].y = HEIGHT){snake.coor[0].y = 0;}break;case LEFT:snake.coor[0].x -= snake.speed;if (snake.coor[0].x = WIDTH){snake.coor[0].x = 0;}break;}}//改变蛇的方向void keyControl(){if ((GetAsyncKeyState('W') || GetAsyncKeyState(VK_UP)) && snake.dir!=DOWN){snake.dir = UP;} if ((GetAsyncKeyState('S') || GetAsyncKeyState(VK_DOWN)) && snake.dir != UP){snake.dir = DOWN;}if ((GetAsyncKeyState('A') || GetAsyncKeyState(VK_LEFT)) && snake.dir != RIGHT){snake.dir = LEFT;}if ((GetAsyncKeyState('D') || GetAsyncKeyState(VK_RIGHT)) && snake.dir != LEFT){snake.dir = RIGHT;}}void EatFood(){if (snake.coor[0].x >= food.x - food.r && snake.coor[0].x = food.y - food.r && snake.coor[0].y <= food.y + food.r &&food.flag){mciSendString(L"close eat", 0, 0, 0);mciSendString(L"open ./ress/eatfood.mp3 alias eat", 0, 0, 0);mciSendString(L"play eat", 0, 0, 0);snake.size++;food.flag = 0;}//如果食物被吃了，就重新生成一个食物if (!food.flag){food.color = RGB(rand() % 256, rand() % 256, rand() % 256);food.flag = 1;food.r = rand() % 10 + 5;food.x = rand() % WIDTH;food.y = rand() % HEIGHT;}}//使程序暂停void stop(){if (_kbhit())//检测是否有按键{if (_getch() == ' '){while (_getch() != ' ');}}}void die(){for (int i = 4; i  200){SnakeMove();t1 = t2;}t2 = GetTickCount();keyControl();EatFood();stop();die();//Sleep(500);//使整个程序，延迟，而我要的是移动延迟}return 0;}

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